Free Marking Schemes Form 3 Physics Paper 3 Exams

By | October 5, 2023

Name___________________________________________ Index No.____________                            

Candidates signature ____________________                          Date __________________

PHYSICS

PAPER 3

PRACTICAL 

2 ½ HOURS

JOINT EXAMINATION TERM 3

INSTRUCTIONS TO CANDIDATES

  • Answer all questions in both sections in the spaces provided in the question paper.
  • Read the whole paper carefully before commencing your work.
  • Marks are given for a clear record of the observations actually made, their suitability and accuracy and their use of them.
  • Mathematical tables and electronic calculators may be used.

FOR EXAMINER’S USE ONLY

QuestionMaximum ScoreCandidate’s Score
1.20 
2.20 
 TOTAL 40 

This paper consists of 7 printed pages. Learners should check to ensure that all pages are printed as indicated and that no questions are missing.

Question 1

You are provided with the following;

  • Masses; 10g, 20g(2), 50g and 100g
  • A helical spring with a pointer
  • The metre rule or half-metre rule

Proceeds as follows;

  1. a) Suspend the helical spring vertically, alongside the clamped half-metre rule as shown in Figure 1 below. Determine the length, L0 of the spring before loading it.

L0=________________________________(cm)                                                      (1mk)

  1. i) Load the spring with a mass of 20g and determine the new reading on the metre rule (L).
  1. ii) Record this in the table below.

iii) Calculate the extension, e= L-L0 due to the mass of 20g and record the value in the table given below.

  1. Repeat steps b(i-iii) for other masses and complete the table.             (8mks)
Mass (g)02030405060708090100
Weight (N) (Force)          
Reading L (cm)          
Extension e (cm)          
  1. Plot a graph of Force(N) against extension e (cm).             (5mks)
  • Determine the slope S of the graph.             (3mks)
  1. Given that K=Se, determine the value of K where S is the slope of the graph and e is the extension of the spring when loaded with a 50g mass.             (3mks)

Question 2

You are provided with the following;

  • A Nichrome wire mounted on a millimetre scale YZ.
  • A carbon resistor R (10Ω)
  • 8 connecting wires
  • Ammeter
  • Voltmeter
  • 2 dry cells
  • Cell holders
  • Switch
  1. (a) Set up the circuit as shown below.
  2. Record the voltmeter reading when the switch is open.

E=_____________________________________                                         (1mk)

  1. Close the switch and record the voltmeter and ammeter readings.

Voltmeter reading, V=_______________________________                     (1mk)

Ammeter reading, I=________________________________                      (1mk)

  • Explain why V is less than E.             (2mk)

______________________________________________________________________________________________________________________________________________________________________________________________________

  1. Now connect the voltmeter across the carbon resistor R and record the voltmeter reading V1 when the switch is on.             (1mk)

V1=

  1. Determine R given that; R=             (3mks)

(b)

  • Measure and record the diameter, d of the resistance wire (YZ) using a micrometre screw gauge.

d= ___________________________________mm

d=___________________________________m                                           (2mks)

  1. ii) Set up the circuit as shown in the figure;
  • Determine the current I flowing in the circuit.

I=__________________________________                                                 (1mk)

  1. Now connect the voltmeter across wire (YZ) and record the p.d, V2 across wire YZ.

V2= ________________________________                                                 (1mk)

  1. Determine the resistance R of the wire YZ.             (3mks)
  1. Determine k, the resistance per metre of wire YZ. (2mks)
  • Determine Q given that Q=(where d is in metres)                    (2mks)

________________________________________________________________________

JOINT EXAMINATION

FORM 3PP3 PHYSICS

TERM 3 MARKING SCHEME

  1. a) L0 – ½mk answer to 1d.p

½mk correct unit (cm)

  1. ii) (8mks)
Mass (g)02030405060708090100
Weight (force) N          
Reading, L cm          
Extension, e(cm) 1.02.64.86.38.110.212.314.216.4

2mks@ Row (force) – correct evaluation and substitution

F = mg

L to 1 d.p

e correct (L-L0) to 1 d.p

  1. v) Graph of Force(N) vs extension, e (cm). (5mks)

Correct labelling of axis – 1mk

Scale – simple and uniform – 1mk

Plotting (2mks) (7-10 points) – 2mks

(5-6 points) – 1mk

(0-4 points) – 0 mk

Line – straight line passing through the origin – 1mk

  1. vi) Slope, s== 0.8N/cm                         (3mk)

Clear points from the graph – 1mk

Correct evaluation – 1mk

Answer – ½mk

Correct unit – ½mk

vii) Correct substitution of k=se – 1mk

Correct evaluation – 1mk

Answer – ½mk

Correct unit – ½mk

  1. a)
  2. E = 3.0- ½mk

Correct unit – ½mk

  1. V = 2.5v1 1 d.p (1mk) and correct unit

I = 0.20A 0.02 2 d.p (1mk) and correct unit

  • V is less than E due to the lost voltage; voltage against the internal resistance of the cell. (2mk)
  1. V1 = 1.4V1 Correct reading to 1 d.p – ½mk

Correct unit – ½mk

  1. R=1

Correct substitution – ½mk

Correct evaluation – ½mk

Answer in 4s.f – ½mk

Correct unit – ½mk

b          (i)        d=0.36mm

d= in metres – correct conversion to 5 d.p  (1mk)

(iii)      I = 0.10A     Correct reading – ½mk

Correct unit – ½mk

iv)V2 = 1.9v  0.1      Correct reading – ½mk

Correct unit – ½mk

  1. v) R= Correct substitution – 1mk

Correct evaluation – 1mk

Answer in 4s.f – ½mk

Correct unit – ½mk

  1. K=Correct evaluation – 1mk

Answer – ½mk 4s.f

Correct unit – ½mk (Ωm-1)

  • Q= Correct evaluation – 1mk

Answer in 4s.f – ½mk

Correct unit – ½mk  (Ωm)